marc Posted January 4, 2009 Share Posted January 4, 2009 (edited) Já resolvi. Obrigado pelo apoio. Edited January 7, 2009 by marc Link to comment Share on other sites More sharing options...
_Mighty_ Posted January 4, 2009 Share Posted January 4, 2009 Isso acho que com um ciclo for se faz bem ;) Link to comment Share on other sites More sharing options...
baquito Posted January 4, 2009 Share Posted January 4, 2009 for k = 0:1000 f(k) = cos ( k/ 1000 * pi) nao está com código 100% do matlab, mas algo do género. depois fazes plot à variavel f que fica um array de valores. Link to comment Share on other sites More sharing options...
marc Posted January 5, 2009 Author Share Posted January 5, 2009 para o espaçamento de chebyshev tenho:function x = chebyshev(n) x(n:-1:1) = cos( (2* (0:n-1)+1) / (2*n) * pi );mas não percebo o que significa o x(n:-1:1)...preciso de converter essa pra chebyshev-lobatto f(x) = cos ( k/n * pi) com k=0,1,2,...,n Link to comment Share on other sites More sharing options...
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